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The mole fraction of glucose in aqueous solution is 0.2 , then molality will be Solution It is given that the mole fraction of glucose is 0.2 Hence the mole fraction of water is = 1−0.2= 0.8 The nuer of moles of glucose can be calculated from the mole fraction as: M olefractionofglucose =XG = nG nG+nw =0.2 (1)
Mole fraction of ethyl alcohol in aqueous ethyl alcohol (C2H5OH) solution is 0.25 . Hence percentage of ethyl alcohol by weight is: Class 11 >> Chemistry >> Some Basic Concepts of Chemistry >> Stoichiometry and Stoichiometric Calculations >> Mole fraction of ethyl alcohol in aqueou Question
26/4/2020· Mole fraction of ethyl alcohol in aqueous ethyl alcohol solution is `0.25`. Hence percentage of ethyl alcohol by weight is :
Moles of C₂H₅OH = 46 g / 46 g = 1 mole Moles of H₂O = 54 g / 18 g = 3 moles Step 3: Divide nuer of moles of solute by total nuer of moles in solution. Mole fraction of C₂H₅OH = 1 / (3+1) = 1 / 4 = 0.25 The mole fraction of 46% w/w ethyl alcohol in water solution is 0.25. 7.9K views View upvotes Tanzeem Khan
Mole fraction of ethyl alcohol in aqueous ethyl alcohol solution is `0.25`. Hence percentage of ethyl alcohol by weight is : A. `54%` B. `25%` C. `75%` D. `46%`
Calculate the mole fractions of sugar and water. Solution: 1) Molality is moles solute / kg of solvent. Therefore we know our solution is: 1.62 mol C 12 H 22 O 11 1.00 kg = 1000 g of water 2) Calculate the moles of water present: 1000 g / 18.0152 g/mol = 55.50868 mol 3) Determine the mole fraction of the sugar:
Nuer of moles of ethanol = 1 /46 = 0.0217 Nuer of moles of water = 100 /18 = 5.55 Mole fraction of ethanol = 0.0217 / 0.0217 + 5.55 = 0.0217/ 5.57 = 0.004 ( solute ) Mole fraction of water = 0.996 ( solvent ) Molality=no of moles of solute/kg of Solvent Kg of Solvent=100g×1/1000kg =0.1kg m=0.0217/0.1 molality=0.217m 2 Antonio Daniels
6/8/2017· We want 0.125 ⋅ mol of ethyl alcohol, but solution concentration is 2.14 ⋅ mol ⋅ L−1 with respect to ethyl alcohol, and so we takes the quotient.. 0.125 ⋅ mol 2.14 ⋅ mol ⋅ L−1 = 0.0584 ⋅ 1 L−1 = 0.0584 ⋅ L ×103 ⋅ mL ⋅ L−1 = 58.4 ⋅ mL d. We want mole fraction with respect to water χH2O = moles of water moles of water + moles of ethanol
Correct option is A) Mass of ethyl alcohol/litre = 50050×1000=100g No. of moles of alcohol/litre = Molarmassing/mol(Massing/litre) = 46100=2.18 Thus, the solution contains 2.18 moles of ethyl alcohol per litre of the solution. So, the molarity of the solution is 2.18 mol/L. Solve any question of Some Basic Concepts of Chemistry with:-
SOLUTION Given that the mole fraction of ethyl alcohol(C2H5OH) is 0.25 i.e. solution contains 0.25 mol EtOH and 0.75 mol H2O Mol wt of EtOH is 46g/mol Therefore 0.25 mol = 0.25×46= 11.5 g of EtOH Mol wt of H2O is 18 g/mol There fore 0.75 mol = 0.75×18
Mole fraction of ethyl alcohol in aqueous ethyl alcohol (C 2H 5OH) solution is 0.25. Hence percentage of ethyl alcohol by weight is: A 54% B 25% C 75% D 46% Hard Solution Verified …
ethyl alcohol (MW=46) Which of the following substances will have the lowest boiling point? a) neon b) water c) ammonia d) helium helium Identify the INCORRECT statement below: a) When the vapor pressure of a liquid equals the surrounding pressure, the liquid boils. b) The boiling point is the temperature at which the vapor pressure of the liquid
Mole fraction of ethyl alcohol in aqueous ethyl alcohol solution is 0. 25 hence the percentage of ethyl alcohol by weight is: Solution Given that the mole fraction of ethyl alcohol …
6/7/2022· Concentration of solutions mole fraction of ethyl alcohol in aqueous ethyl al Mole fraction of ethyl alcohol in aqueous ethyl alcohol solution is 0.25 0.25. Hence percentage of ethyl alcohol by weight is Updated On: Jul 6, 2022 0.54 0.25 0.75 0.46 Correct Answer: D Detailed Solution Download Solution in PDF
Mole fraction of ethyl alcohol in aqueous ethyl alcohol solution is `0.25`. Hence percentage of ethyl alcohol by weight is : askedJun 29, 2019in Chemistryby Anaisha(67.2kpoints) class-11 mole-concept stoichiometry 0votes 1answer The mole fraction of glucose in an aqueous solution is `9/109.` The molality of solution is:
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